Concept2 Forum

Could someone supply the formula that the PM uses to convert between calories and meters? I'm not trying to convert erg calories to actual calories so the calore calculator on the C2 site (http://www.concept2.com/indoor-rowers/t ... calculator) is not of use here. I just want to figure out the distance of a piece given the total calories only.

Thanks Citroen. It's not the "plug in calories, get out meters" formula that I was looking for but there's enough info there for me to do the rest of the work. One thing that I didn't realize is that the time spent rowing would be required as well since there are extra calories thrown into the formula for just being alive. In other words, you would be given calorie credit just for sitting there even if you aren't pulling the handle though in practice the PM probably only gives those when the flywheel is spinning.

kick-send wrote:Thanks Citroen. It's not the "plug in calories, get out meters" formula that I was looking for but there's enough info there for me to do the rest of the work. One thing that I didn't realize is that the time spent rowing would be required as well since there are extra calories thrown into the formula for just being alive. In other words, you would be given calorie credit just for sitting there even if you aren't pulling the handle though in practice the PM probably only gives those when the flywheel is spinning.

The extra 300C/hr is tossed in for the work that you are presumably using, just accelerating and decelerating your body back and forth on the slide. It is based on a "standard rower," and I don't remember how C2 defines that - something like a 180# male who is using a middle of the road stroke rate. It is probably reasonably valid for someone who matches their definition,
but not for everyone else. The rest of the Calories are directly proportional to the wattage, based on their definitions. The conversion factor is 1.16 (i.e. watts per C/hr).

Re the thread title: There can't be any conversion of calories to meters unless there is some data provided to show how much effort is used to produce those meters. 2000 meters done in 6 minutes will burn 41.4 Calories. If it takes 10 minutes it will burn only 14.9 Calories. Note that this means actual Calories burned to produce the work on the wheel. The "free?" Calories that C2 adds in with the monitor would be an extra 30 Calories for the 6' piece and a whopping 50 Calories for the 10' effort.

Bob S.

In the Memory function, pressing the Units button switches the readout between Watts, pace and cal/h. All three are rates, so for total kCal (or Wh) multiply by time in hours.

On the main readout just after a Wo (and during), we also see total metres and total cal for the Wo, again by pressing the Units button, so you can estimate the ratio. This ratio will be constant only if you work always at the same pace; so near enough for kCal sums. Mine is about 1 kCal per 16m.

The C2 calories include the free 300kCal/h. To avoid this, just multiply Watts by 4; where 4 is our estimated efficiency as fuel cells, so 4W is our overall heat rate. Then multiply by hours and convert to BTU or kCal as required.

A good game is to try to get the cal counter to increase by one, every stroke.

Multiply kCal by 16. You can check future readings to see if this ratio is correct for you, or where your range is.

This also means that if you want to burn 1000 kCal, you need to go 16 km.

I needed something similar:

To Calculate the calories based on time, distance and body weight

The formulas I used:
P = 2.8 * (V^3) = 2.8 * (d/t)^3

P: power in watts
V: Velocity meters/sec
d: distance in meters
t: time in seconds

Relationship between units:
1 kcal/h = 1.1623 W

You have 2 options from whether to count with the normal consumpson of human body or not.

Effective: is without the normal consumtion
Overall: is with the normal consumption

Effective: True calories/hour burned = (P*1.1623) - 300 + (1.714 * m)
Overall: True calories/hour burned = (P*1.1623) + (1.714 * m)

m: mass in lbs

Effective -> calories burned during workout = t*(0.000904*(d/t)^3 + 0.000476*m - 0.083)
Overall -> calories burned during workout = t*(0.000904*(d/t)^3 + 0.000476*m)


At my location we use Kg for measuring weight so this is the equation with kgs

Effective -> calories burned during workout = t*(0.000904*(d/t)^3 + 0.00105*m - 0.083)
Overall -> calories burned during workout = t*(0.000904*(d/t)^3 + 0.00105*m)


An example with one of my workouts:

Weight: 81 Kgs
Distance: 5000 meters
Time: 18:40.8 -> 1120.8 secs

Effective Calories burned = 1120.8*(0.000904*(5000/1120.8)^3 + 0.00105*81 - 0.083) 92 Kcal
Overall calories burned = 1120.8*(0.000904*(5000/1120.8)^3 + 0.00105*81) ~ 185 Kcal